-16t^2=112t

Solution for -16t^2=112t equation:

-16t^2=112t

We move all terms to the left:

-16t^2-(112t)=0

a = -16; b = -112; c = 0;
Δ = b2-4ac
Δ = -1122-4·(-16)·0
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-112)-112}{2*-16}=\frac{0}{-32}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-112)+112}{2*-16}=\frac{224}{-32}
=-7
$